8y^2-2y=1

Solution for 8y^2-2y=1 equation:

8y^2-2y=1

We move all terms to the left:

8y^2-2y-(1)=0

a = 8; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·8·(-1)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*8}=\frac{-4}{16}
=-1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*8}=\frac{8}{16}
=1/2
$